Base | Representation |
---|---|
bin | 10011100001000010001… |
… | …100010010001110111001 |
3 | 11202012201101002220010002 |
4 | 103201002030102032321 |
5 | 133433123410004032 |
6 | 2504040015202345 |
7 | 165615464366051 |
oct | 23410214221671 |
9 | 4665641086102 |
10 | 1341140313017 |
11 | 47785781a28a |
12 | 197b092163b5 |
13 | 996134a381b |
14 | 48ca938a561 |
15 | 24d45aa7862 |
hex | 138423123b9 |
1341140313017 has 2 divisors, whose sum is σ = 1341140313018. Its totient is φ = 1341140313016.
The previous prime is 1341140313011. The next prime is 1341140313059. The reversal of 1341140313017 is 7103130411431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1079803626496 + 261336686521 = 1039136^2 + 511211^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1341140313017 is a prime.
It is not a weakly prime, because it can be changed into another prime (1341140313011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670570156508 + 670570156509.
It is an arithmetic number, because the mean of its divisors is an integer number (670570156509).
Almost surely, 21341140313017 is an apocalyptic number.
It is an amenable number.
1341140313017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341140313017 is an equidigital number, since it uses as much as digits as its factorization.
1341140313017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 1341140313017 its reverse (7103130411431), we get a palindrome (8444270724448).
The spelling of 1341140313017 in words is "one trillion, three hundred forty-one billion, one hundred forty million, three hundred thirteen thousand, seventeen".
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