134114114341307 has 2 divisors, whose sum is σ = 134114114341308. Its totient is φ = 134114114341306.

The previous prime is 134114114341261. The next prime is 134114114341367. The reversal of 134114114341307 is 703143411411431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134114114341307 - 2¹⁸ = 134114114079163 is a prime.

It is a super-3 number, since 3×134114114341307³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (134114114341367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67057057170653 + 67057057170654.

It is an arithmetic number, because the mean of its divisors is an integer number (67057057170654).

Almost surely, 2^{134114114341307} is an apocalyptic number.

134114114341307 is a deficient number, since it is larger than the sum of its proper divisors (1).

134114114341307 is an equidigital number, since it uses as much as digits as its factorization.

134114114341307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 38.

Adding to 134114114341307 its reverse (703143411411431), we get a palindrome (837257525752738).

The spelling of 134114114341307 in words is "one hundred thirty-four trillion, one hundred fourteen billion, one hundred fourteen million, three hundred forty-one thousand, three hundred seven".