Base | Representation |
---|---|
bin | 1100001100101001101110… |
… | …1110010010010001010101 |
3 | 1202111010102112021211111201 |
4 | 3003022123232102101111 |
5 | 3224213223112000203 |
6 | 44305054104232501 |
7 | 2552643325214155 |
oct | 303123356222125 |
9 | 52433375254451 |
10 | 13411500500053 |
11 | 4300870438a97 |
12 | 16072a446b731 |
13 | 763911b1c976 |
14 | 345197740765 |
15 | 183ce5a35e1d |
hex | c329bb92455 |
13411500500053 has 2 divisors, whose sum is σ = 13411500500054. Its totient is φ = 13411500500052.
The previous prime is 13411500500033. The next prime is 13411500500117. The reversal of 13411500500053 is 35000500511431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11907068238244 + 1504432261809 = 3450662^2 + 1226553^2 .
It is a cyclic number.
It is not a de Polignac number, because 13411500500053 - 29 = 13411500499541 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13411500499994 and 13411500500030.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411500500033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705750250026 + 6705750250027.
It is an arithmetic number, because the mean of its divisors is an integer number (6705750250027).
Almost surely, 213411500500053 is an apocalyptic number.
It is an amenable number.
13411500500053 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411500500053 is an equidigital number, since it uses as much as digits as its factorization.
13411500500053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 28.
The spelling of 13411500500053 in words is "thirteen trillion, four hundred eleven billion, five hundred million, five hundred thousand, fifty-three".
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