Base | Representation |
---|---|
bin | 10011100001000010110… |
… | …011010101100001110010 |
3 | 11202012202002100222210102 |
4 | 103201002303111201302 |
5 | 133433134020101010 |
6 | 2504041022432402 |
7 | 165615650403626 |
oct | 23410263254162 |
9 | 4665662328712 |
10 | 1341150550130 |
11 | 477862581606 |
12 | 197b10732702 |
13 | 996156492a1 |
14 | 48caa893186 |
15 | 24d4692aba5 |
hex | 13842cd5872 |
1341150550130 has 32 divisors (see below), whose sum is σ = 2450247166080. Its totient is φ = 528422019840.
The previous prime is 1341150550123. The next prime is 1341150550141. The reversal of 1341150550130 is 310550511431.
It is a super-2 number, since 2×13411505501302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1341150550093 and 1341150550102.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13591370 + ... + 13689690.
It is an arithmetic number, because the mean of its divisors is an integer number (76570223940).
Almost surely, 21341150550130 is an apocalyptic number.
1341150550130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1341150550130 is a deficient number, since it is larger than the sum of its proper divisors (1109096615950).
1341150550130 is a wasteful number, since it uses less digits than its factorization.
1341150550130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118754.
The product of its (nonzero) digits is 4500, while the sum is 29.
The spelling of 1341150550130 in words is "one trillion, three hundred forty-one billion, one hundred fifty million, five hundred fifty thousand, one hundred thirty".
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