Base | Representation |
---|---|
bin | 1100001100101001110110… |
… | …1111001111011110101001 |
3 | 1202111010111212220022102221 |
4 | 3003022131233033132221 |
5 | 3224213310240231233 |
6 | 44305101312554041 |
7 | 2552644215441343 |
oct | 303123557173651 |
9 | 52433455808387 |
10 | 13411534305193 |
11 | 4300888528322 |
12 | 16072b3852921 |
13 | 763918b278cb |
14 | 34519c020293 |
15 | 183ce89b242d |
hex | c329dbcf7a9 |
13411534305193 has 2 divisors, whose sum is σ = 13411534305194. Its totient is φ = 13411534305192.
The previous prime is 13411534305179. The next prime is 13411534305283. The reversal of 13411534305193 is 39150343511431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9783301741929 + 3628232563264 = 3127827^2 + 1904792^2 .
It is a cyclic number.
It is not a de Polignac number, because 13411534305193 - 29 = 13411534304681 is a prime.
It is not a weakly prime, because it can be changed into another prime (13411534305593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705767152596 + 6705767152597.
It is an arithmetic number, because the mean of its divisors is an integer number (6705767152597).
Almost surely, 213411534305193 is an apocalyptic number.
It is an amenable number.
13411534305193 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411534305193 is an equidigital number, since it uses as much as digits as its factorization.
13411534305193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 291600, while the sum is 43.
The spelling of 13411534305193 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-four million, three hundred five thousand, one hundred ninety-three".
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