Search a number
-
+
13412100152387 is a prime number
BaseRepresentation
bin1100001100101011111101…
…1101110001110001000011
31202111011222022122022212102
43003022333131301301003
53224220440114334022
644305233405021015
72552664226164536
oct303127735616103
952434868568772
1013412100152387
114301048979732
12160743125476b
137639a9126231
14345213236a1d
15183d2d4d5a92
hexc32bf771c43

13412100152387 has 2 divisors, whose sum is σ = 13412100152388. Its totient is φ = 13412100152386.

The previous prime is 13412100152327. The next prime is 13412100152393. The reversal of 13412100152387 is 78325100121431.

It is a strong prime.

It is an emirp because it is prime and its reverse (78325100121431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13412100152387 - 210 = 13412100151363 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13412100152387.

It is not a weakly prime, because it can be changed into another prime (13412100152327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706050076193 + 6706050076194.

It is an arithmetic number, because the mean of its divisors is an integer number (6706050076194).

Almost surely, 213412100152387 is an apocalyptic number.

13412100152387 is a deficient number, since it is larger than the sum of its proper divisors (1).

13412100152387 is an equidigital number, since it uses as much as digits as its factorization.

13412100152387 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 13412100152387 in words is "thirteen trillion, four hundred twelve billion, one hundred million, one hundred fifty-two thousand, three hundred eighty-seven".