Base | Representation |
---|---|
bin | 111110011101000111… |
… | …1000011100000011111 |
3 | 110211012010100022021102 |
4 | 1330322033003200133 |
5 | 4144134434324411 |
6 | 141340410423315 |
7 | 12455433533234 |
oct | 1747217034037 |
9 | 424163308242 |
10 | 134121011231 |
11 | 519758a5939 |
12 | 21bb0a31b3b |
13 | c8558b550c |
14 | 66c491d78b |
15 | 374ea3dd3b |
hex | 1f3a3c381f |
134121011231 has 2 divisors, whose sum is σ = 134121011232. Its totient is φ = 134121011230.
The previous prime is 134121011221. The next prime is 134121011273. The reversal of 134121011231 is 132110121431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134121011231 - 234 = 116941142047 is a prime.
It is a super-2 number, since 2×1341210112312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134121011221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67060505615 + 67060505616.
It is an arithmetic number, because the mean of its divisors is an integer number (67060505616).
Almost surely, 2134121011231 is an apocalyptic number.
134121011231 is a deficient number, since it is larger than the sum of its proper divisors (1).
134121011231 is an equidigital number, since it uses as much as digits as its factorization.
134121011231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 134121011231 its reverse (132110121431), we get a palindrome (266231132662).
The spelling of 134121011231 in words is "one hundred thirty-four billion, one hundred twenty-one million, eleven thousand, two hundred thirty-one".
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