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1341213016433 is a prime number
BaseRepresentation
bin10011100001000110100…
…001101000000101110001
311202012220102220121110012
4103201012201220011301
5133433301013011213
62504051133344305
7165620336352263
oct23410641500561
94665812817405
101341213016433
11477894867454
12197b29638095
139962557a9b4
1448cb4cb3b33
1524d4c1694a8
hex13846868171

1341213016433 has 2 divisors, whose sum is σ = 1341213016434. Its totient is φ = 1341213016432.

The previous prime is 1341213016399. The next prime is 1341213016483. The reversal of 1341213016433 is 3346103121431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1333417539169 + 7795477264 = 1154737^2 + 88292^2 .

It is a cyclic number.

It is not a de Polignac number, because 1341213016433 - 224 = 1341196239217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1341213016433.

It is not a weakly prime, because it can be changed into another prime (1341213016483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670606508216 + 670606508217.

It is an arithmetic number, because the mean of its divisors is an integer number (670606508217).

Almost surely, 21341213016433 is an apocalyptic number.

It is an amenable number.

1341213016433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341213016433 is an equidigital number, since it uses as much as digits as its factorization.

1341213016433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 1341213016433 its reverse (3346103121431), we get a palindrome (4687316137864).

The spelling of 1341213016433 in words is "one trillion, three hundred forty-one billion, two hundred thirteen million, sixteen thousand, four hundred thirty-three".