Base | Representation |
---|---|
bin | 10011100001000110100… |
… | …001101000000101110001 |
3 | 11202012220102220121110012 |
4 | 103201012201220011301 |
5 | 133433301013011213 |
6 | 2504051133344305 |
7 | 165620336352263 |
oct | 23410641500561 |
9 | 4665812817405 |
10 | 1341213016433 |
11 | 477894867454 |
12 | 197b29638095 |
13 | 9962557a9b4 |
14 | 48cb4cb3b33 |
15 | 24d4c1694a8 |
hex | 13846868171 |
1341213016433 has 2 divisors, whose sum is σ = 1341213016434. Its totient is φ = 1341213016432.
The previous prime is 1341213016399. The next prime is 1341213016483. The reversal of 1341213016433 is 3346103121431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1333417539169 + 7795477264 = 1154737^2 + 88292^2 .
It is a cyclic number.
It is not a de Polignac number, because 1341213016433 - 224 = 1341196239217 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1341213016433.
It is not a weakly prime, because it can be changed into another prime (1341213016483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670606508216 + 670606508217.
It is an arithmetic number, because the mean of its divisors is an integer number (670606508217).
Almost surely, 21341213016433 is an apocalyptic number.
It is an amenable number.
1341213016433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341213016433 is an equidigital number, since it uses as much as digits as its factorization.
1341213016433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 1341213016433 its reverse (3346103121431), we get a palindrome (4687316137864).
The spelling of 1341213016433 in words is "one trillion, three hundred forty-one billion, two hundred thirteen million, sixteen thousand, four hundred thirty-three".
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