134121311120 has 20 divisors (see below), whose sum is σ = 311832048540. Its totient is φ = 53648524416.

The previous prime is 134121311101. The next prime is 134121311183. The reversal of 134121311120 is 21113121431.

It can be written as a sum of positive squares in 2 ways, for example, as 20859447184 + 113261863936 = 144428^2 + 336544^2 .

It is a tau number, because it is divible by the number of its divisors (20).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 134121311092 and 134121311101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 838258115 + ... + 838258274.

It is an arithmetic number, because the mean of its divisors is an integer number (15591602427).

Almost surely, 2^134121311120 is an apocalyptic number.

134121311120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134121311120 is an abundant number, since it is smaller than the sum of its proper divisors (177710737420).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134121311120 is a wasteful number, since it uses less digits than its factorization.

134121311120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1676516402 (or 1676516396 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 134121311120 its reverse (21113121431), we get a palindrome (155234432551).

It can be divided in two parts, 134121311 and 120, that added together give a palindrome (134121431).

The spelling of 134121311120 in words is "one hundred thirty-four billion, one hundred twenty-one million, three hundred eleven thousand, one hundred twenty".