Base | Representation |
---|---|
bin | 111110011101001011… |
… | …1000110111011110111 |
3 | 110211012021022120021201 |
4 | 1330322113012323313 |
5 | 4144141004404143 |
6 | 141340523553331 |
7 | 12455460505303 |
oct | 1747227067367 |
9 | 424167276251 |
10 | 134123122423 |
11 | 51977008024 |
12 | 21bb168b847 |
13 | c856174444 |
14 | 66c4d0cd03 |
15 | 374ed0964d |
hex | 1f3a5c6ef7 |
134123122423 has 2 divisors, whose sum is σ = 134123122424. Its totient is φ = 134123122422.
The previous prime is 134123122417. The next prime is 134123122457. The reversal of 134123122423 is 324221321431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134123122423 - 25 = 134123122391 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134123122391 and 134123122400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134123422423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67061561211 + 67061561212.
It is an arithmetic number, because the mean of its divisors is an integer number (67061561212).
Almost surely, 2134123122423 is an apocalyptic number.
134123122423 is a deficient number, since it is larger than the sum of its proper divisors (1).
134123122423 is an equidigital number, since it uses as much as digits as its factorization.
134123122423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 28.
Adding to 134123122423 its reverse (324221321431), we get a palindrome (458344443854).
The spelling of 134123122423 in words is "one hundred thirty-four billion, one hundred twenty-three million, one hundred twenty-two thousand, four hundred twenty-three".
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