13412432044111 has 2 divisors, whose sum is σ = 13412432044112. Its totient is φ = 13412432044110.

The previous prime is 13412432044091. The next prime is 13412432044117. The reversal of 13412432044111 is 11144023421431.

It is a strong prime.

It is an emirp because it is prime and its reverse (11144023421431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13412432044111 - 2⁵ = 13412432044079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13412432044117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706216022055 + 6706216022056.

It is an arithmetic number, because the mean of its divisors is an integer number (6706216022056).

Almost surely, 2^{13412432044111} is an apocalyptic number.

13412432044111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13412432044111 is an equidigital number, since it uses as much as digits as its factorization.

13412432044111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13412432044111 its reverse (11144023421431), we get a palindrome (24556455465542).

The spelling of 13412432044111 in words is "thirteen trillion, four hundred twelve billion, four hundred thirty-two million, forty-four thousand, one hundred eleven".