Base | Representation |
---|---|
bin | 1100001100101101001111… |
… | …1011010101101111000011 |
3 | 1202111012212020121110110111 |
4 | 3003023103323111233003 |
5 | 3224222141010234321 |
6 | 44305331431012151 |
7 | 2553005565141265 |
oct | 303132373255703 |
9 | 52435766543414 |
10 | 13412443446211 |
11 | 4301204733437 |
12 | 160750820a057 |
13 | 763a322a1b84 |
14 | 345246a79b35 |
15 | 183d4d6e75e1 |
hex | c32d3ed5bc3 |
13412443446211 has 2 divisors, whose sum is σ = 13412443446212. Its totient is φ = 13412443446210.
The previous prime is 13412443446161. The next prime is 13412443446251. The reversal of 13412443446211 is 11264434421431.
It is an a-pointer prime, because the next prime (13412443446251) can be obtained adding 13412443446211 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13412443446211 - 213 = 13412443438019 is a prime.
It is not a weakly prime, because it can be changed into another prime (13412443446251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706221723105 + 6706221723106.
It is an arithmetic number, because the mean of its divisors is an integer number (6706221723106).
Almost surely, 213412443446211 is an apocalyptic number.
13412443446211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412443446211 is an equidigital number, since it uses as much as digits as its factorization.
13412443446211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 221184, while the sum is 40.
Adding to 13412443446211 its reverse (11264434421431), we get a palindrome (24676877867642).
The spelling of 13412443446211 in words is "thirteen trillion, four hundred twelve billion, four hundred forty-three million, four hundred forty-six thousand, two hundred eleven".
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