Base | Representation |
---|---|
bin | 1100001100101101011101… |
… | …1000100010011101000110 |
3 | 1202111020000021201110012021 |
4 | 3003023113120202131012 |
5 | 3224222300331312014 |
6 | 44305341301513354 |
7 | 2553010201046410 |
oct | 303132730423506 |
9 | 52436007643167 |
10 | 13412501432134 |
11 | 4301234439092 |
12 | 160752371285a |
13 | 763a412c517c |
14 | 3452506519b0 |
15 | 183d5384d624 |
hex | c32d7622746 |
13412501432134 has 8 divisors (see below), whose sum is σ = 22992859597968. Its totient is φ = 5748214899480.
The previous prime is 13412501432081. The next prime is 13412501432149. The reversal of 13412501432134 is 43123410521431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13412501432134.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 479017908277 + ... + 479017908304.
It is an arithmetic number, because the mean of its divisors is an integer number (2874107449746).
Almost surely, 213412501432134 is an apocalyptic number.
13412501432134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13412501432134 is a deficient number, since it is larger than the sum of its proper divisors (9580358165834).
13412501432134 is an equidigital number, since it uses as much as digits as its factorization.
13412501432134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 958035816590.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 13412501432134 its reverse (43123410521431), we get a palindrome (56535911953565).
The spelling of 13412501432134 in words is "thirteen trillion, four hundred twelve billion, five hundred one million, four hundred thirty-two thousand, one hundred thirty-four".
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