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13413015010117 is a prime number
BaseRepresentation
bin1100001100101111010111…
…1111101011101101000101
31202111021100002002220202001
43003023311333223231011
53224224323320310432
644305504245345301
72553026005304332
oct303136577535505
952437302086661
1013413015010117
1143014783298a8
121607647708231
13763ac3822578
1434529c93d989
15183d839999e7
hexc32f5febb45

13413015010117 has 2 divisors, whose sum is σ = 13413015010118. Its totient is φ = 13413015010116.

The previous prime is 13413015010097. The next prime is 13413015010127. The reversal of 13413015010117 is 71101051031431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13252759708356 + 160255301761 = 3640434^2 + 400319^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13413015010117 is a prime.

It is a super-2 number, since 2×134130150101172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13413015010127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706507505058 + 6706507505059.

It is an arithmetic number, because the mean of its divisors is an integer number (6706507505059).

Almost surely, 213413015010117 is an apocalyptic number.

It is an amenable number.

13413015010117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13413015010117 is an equidigital number, since it uses as much as digits as its factorization.

13413015010117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 28.

Adding to 13413015010117 its reverse (71101051031431), we get a palindrome (84514066041548).

The spelling of 13413015010117 in words is "thirteen trillion, four hundred thirteen billion, fifteen million, ten thousand, one hundred seventeen".