Base | Representation |
---|---|
bin | 11000111110111101… |
… | …11010111010110111 |
3 | 1021121210010010211101 |
4 | 30133132322322313 |
5 | 204432223214424 |
6 | 10054545150531 |
7 | 653250323266 |
oct | 143736727267 |
9 | 37553103741 |
10 | 13413101239 |
11 | 576338953a |
12 | 272402b447 |
13 | 1359b4c5c5 |
14 | 9135805dd |
15 | 537852344 |
hex | 31f7baeb7 |
13413101239 has 2 divisors, whose sum is σ = 13413101240. Its totient is φ = 13413101238.
The previous prime is 13413101227. The next prime is 13413101293. The reversal of 13413101239 is 93210131431.
Together with next prime (13413101293) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is an emirp because it is prime and its reverse (93210131431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13413101239 - 213 = 13413093047 is a prime.
It is a super-2 number, since 2×134131012392 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13413101939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706550619 + 6706550620.
It is an arithmetic number, because the mean of its divisors is an integer number (6706550620).
Almost surely, 213413101239 is an apocalyptic number.
13413101239 is a deficient number, since it is larger than the sum of its proper divisors (1).
13413101239 is an equidigital number, since it uses as much as digits as its factorization.
13413101239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 13413101239 in words is "thirteen billion, four hundred thirteen million, one hundred one thousand, two hundred thirty-nine".
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