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1341311022157 is a prime number
BaseRepresentation
bin10011100001001100010…
…111011111010001001101
311202020011021022211000211
4103201030113133101031
5133434001110202112
62504104554122421
7165622636400251
oct23411427372115
94666137284024
101341311022157
11477935116617
12197b56420411
139963c973852
1448cc3d06261
1524d55a780a7
hex1384c5df44d

1341311022157 has 2 divisors, whose sum is σ = 1341311022158. Its totient is φ = 1341311022156.

The previous prime is 1341311022083. The next prime is 1341311022169. The reversal of 1341311022157 is 7512201131431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 700445129476 + 640865892681 = 836926^2 + 800541^2 .

It is a cyclic number.

It is not a de Polignac number, because 1341311022157 - 211 = 1341311020109 is a prime.

It is a super-2 number, since 2×13413110221572 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1341311022187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670655511078 + 670655511079.

It is an arithmetic number, because the mean of its divisors is an integer number (670655511079).

Almost surely, 21341311022157 is an apocalyptic number.

It is an amenable number.

1341311022157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341311022157 is an equidigital number, since it uses as much as digits as its factorization.

1341311022157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 1341311022157 its reverse (7512201131431), we get a palindrome (8853512153588).

The spelling of 1341311022157 in words is "one trillion, three hundred forty-one billion, three hundred eleven million, twenty-two thousand, one hundred fifty-seven".