Base | Representation |
---|---|
bin | 1100001100110000110110… |
… | …0011101011000001000011 |
3 | 1202111022100121221202120112 |
4 | 3003030031203223001003 |
5 | 3224231131020223301 |
6 | 44310011410301535 |
7 | 2553041545344521 |
oct | 303141543530103 |
9 | 52438317852515 |
10 | 13413410320451 |
11 | 4301660491359 |
12 | 1607737b878ab |
13 | 763b576b13cb |
14 | 3452d9243311 |
15 | 183da85339bb |
hex | c330d8eb043 |
13413410320451 has 2 divisors, whose sum is σ = 13413410320452. Its totient is φ = 13413410320450.
The previous prime is 13413410320367. The next prime is 13413410320463. The reversal of 13413410320451 is 15402301431431.
It is a strong prime.
It is an emirp because it is prime and its reverse (15402301431431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13413410320451 is a prime.
It is not a weakly prime, because it can be changed into another prime (13413410320951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706705160225 + 6706705160226.
It is an arithmetic number, because the mean of its divisors is an integer number (6706705160226).
Almost surely, 213413410320451 is an apocalyptic number.
13413410320451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13413410320451 is an equidigital number, since it uses as much as digits as its factorization.
13413410320451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 13413410320451 its reverse (15402301431431), we get a palindrome (28815711751882).
The spelling of 13413410320451 in words is "thirteen trillion, four hundred thirteen billion, four hundred ten million, three hundred twenty thousand, four hundred fifty-one".
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