Base | Representation |
---|---|
bin | 1100001100110011111001… |
… | …1111001110111001110011 |
3 | 1202111101110211122210220122 |
4 | 3003030332133032321303 |
5 | 3224234321144142212 |
6 | 44310225053400455 |
7 | 2553101104141052 |
oct | 303147637167163 |
9 | 52441424583818 |
10 | 13414231240307 |
11 | 4301a41910617 |
12 | 1607926a9912b |
13 | 763c587aa2c1 |
14 | 345376296399 |
15 | 183e0563e272 |
hex | c333e7cee73 |
13414231240307 has 2 divisors, whose sum is σ = 13414231240308. Its totient is φ = 13414231240306.
The previous prime is 13414231240303. The next prime is 13414231240321. The reversal of 13414231240307 is 70304213241431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13414231240307 - 22 = 13414231240303 is a prime.
It is a super-3 number, since 3×134142312403073 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13414231240301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707115620153 + 6707115620154.
It is an arithmetic number, because the mean of its divisors is an integer number (6707115620154).
Almost surely, 213414231240307 is an apocalyptic number.
13414231240307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13414231240307 is an equidigital number, since it uses as much as digits as its factorization.
13414231240307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 13414231240307 its reverse (70304213241431), we get a palindrome (83718444481738).
The spelling of 13414231240307 in words is "thirteen trillion, four hundred fourteen billion, two hundred thirty-one million, two hundred forty thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •