13414231240301 has 2 divisors, whose sum is σ = 13414231240302. Its totient is φ = 13414231240300.

The previous prime is 13414231240133. The next prime is 13414231240303. The reversal of 13414231240301 is 10304213241431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12379384849225 + 1034846391076 = 3518435^2 + 1017274^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13414231240301 is a prime.

Together with 13414231240303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13414231240303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707115620150 + 6707115620151.

It is an arithmetic number, because the mean of its divisors is an integer number (6707115620151).

Almost surely, 2^{13414231240301} is an apocalyptic number.

It is an amenable number.

13414231240301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13414231240301 is an equidigital number, since it uses as much as digits as its factorization.

13414231240301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13414231240301 its reverse (10304213241431), we get a palindrome (23718444481732).

The spelling of 13414231240301 in words is "thirteen trillion, four hundred fourteen billion, two hundred thirty-one million, two hundred forty thousand, three hundred one".