Base | Representation |
---|---|
bin | 11000111111000110… |
… | …10011111000000011 |
3 | 1021121212021121102110 |
4 | 30133203103320003 |
5 | 204433022031120 |
6 | 10055025550403 |
7 | 653263155342 |
oct | 143743237003 |
9 | 37555247373 |
10 | 13414252035 |
11 | 5763aa5108 |
12 | 27244a5403 |
13 | 135a163352 |
14 | 91379db59 |
15 | 5379cd2e0 |
hex | 31f8d3e03 |
13414252035 has 128 divisors (see below), whose sum is σ = 24111820800. Its totient is φ = 6340239360.
The previous prime is 13414252003. The next prime is 13414252063. The reversal of 13414252035 is 53025241431.
It is not a de Polignac number, because 13414252035 - 25 = 13414252003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13414251993 and 13414252011.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 49498950 + ... + 49499220.
It is an arithmetic number, because the mean of its divisors is an integer number (188373600).
Almost surely, 213414252035 is an apocalyptic number.
13414252035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13414252035 is a deficient number, since it is larger than the sum of its proper divisors (10697568765).
13414252035 is a wasteful number, since it uses less digits than its factorization.
13414252035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 493.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 13414252035 its reverse (53025241431), we get a palindrome (66439493466).
The spelling of 13414252035 in words is "thirteen billion, four hundred fourteen million, two hundred fifty-two thousand, thirty-five".
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