Base | Representation |
---|---|
bin | 10011100001010011101… |
… | …101110000101110010010 |
3 | 11202020110212022001021010 |
4 | 103201103231300232102 |
5 | 133434224140120310 |
6 | 2504125120311350 |
7 | 165625664266614 |
oct | 23412355605622 |
9 | 4666425261233 |
10 | 1341434301330 |
11 | 477998768032 |
12 | 197b8b772556 |
13 | 9965c3781c6 |
14 | 48cd6436db4 |
15 | 24d617ca320 |
hex | 13853b70b92 |
1341434301330 has 16 divisors (see below), whose sum is σ = 3219442323264. Its totient is φ = 357715813680.
The previous prime is 1341434301299. The next prime is 1341434301359. The reversal of 1341434301330 is 331034341431.
It is a Harshad number since it is a multiple of its sum of digits (30), and also a Moran number because the ratio is a prime number: 44714476711 = 1341434301330 / (1 + 3 + 4 + 1 + 4 + 3 + 4 + 3 + 0 + 1 + 3 + 3 + 0).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22357238326 + ... + 22357238385.
It is an arithmetic number, because the mean of its divisors is an integer number (201215145204).
Almost surely, 21341434301330 is an apocalyptic number.
1341434301330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1341434301330 is an abundant number, since it is smaller than the sum of its proper divisors (1878008021934).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1341434301330 is a wasteful number, since it uses less digits than its factorization.
1341434301330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44714476721.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 1341434301330 its reverse (331034341431), we get a palindrome (1672468642761).
The spelling of 1341434301330 in words is "one trillion, three hundred forty-one billion, four hundred thirty-four million, three hundred one thousand, three hundred thirty".
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