Base | Representation |
---|---|
bin | 11000111111001110… |
… | …11100001000100001 |
3 | 1021121221022121012021 |
4 | 30133213130020201 |
5 | 204433311200213 |
6 | 10055105101441 |
7 | 653305314124 |
oct | 143747341041 |
9 | 37557277167 |
10 | 13415334433 |
11 | 5764674356 |
12 | 2724927881 |
13 | 135a451c17 |
14 | 9139a23bb |
15 | 537b43d8d |
hex | 31f9dc221 |
13415334433 has 2 divisors, whose sum is σ = 13415334434. Its totient is φ = 13415334432.
The previous prime is 13415334419. The next prime is 13415334463. The reversal of 13415334433 is 33443351431.
13415334433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10756178944 + 2659155489 = 103712^2 + 51567^2 .
It is a cyclic number.
It is not a de Polignac number, because 13415334433 - 233 = 4825399841 is a prime.
It is not a weakly prime, because it can be changed into another prime (13415334463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707667216 + 6707667217.
It is an arithmetic number, because the mean of its divisors is an integer number (6707667217).
Almost surely, 213415334433 is an apocalyptic number.
It is an amenable number.
13415334433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13415334433 is an equidigital number, since it uses as much as digits as its factorization.
13415334433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77760, while the sum is 34.
Adding to 13415334433 its reverse (33443351431), we get a palindrome (46858685864).
The spelling of 13415334433 in words is "thirteen billion, four hundred fifteen million, three hundred thirty-four thousand, four hundred thirty-three".
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