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13415533544953 is a prime number
BaseRepresentation
bin1100001100111000110000…
…0111001000010111111001
31202111111211121011202001001
43003032030013020113321
53224300003041414303
644311002214325001
72553145266430441
oct303161407102771
952444747152031
1013415533544953
11430254aa42351
12160802b059761
13764105541277
1434545b217121
15183e7eb3731d
hexc338c1c85f9

13415533544953 has 2 divisors, whose sum is σ = 13415533544954. Its totient is φ = 13415533544952.

The previous prime is 13415533544951. The next prime is 13415533545059. The reversal of 13415533544953 is 35944533551431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10310283387369 + 3105250157584 = 3210963^2 + 1762172^2 .

It is a cyclic number.

It is not a de Polignac number, because 13415533544953 - 21 = 13415533544951 is a prime.

Together with 13415533544951, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13415533544894 and 13415533544903.

It is not a weakly prime, because it can be changed into another prime (13415533544951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707766772476 + 6707766772477.

It is an arithmetic number, because the mean of its divisors is an integer number (6707766772477).

Almost surely, 213415533544953 is an apocalyptic number.

It is an amenable number.

13415533544953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13415533544953 is an equidigital number, since it uses as much as digits as its factorization.

13415533544953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29160000, while the sum is 55.

The spelling of 13415533544953 in words is "thirteen trillion, four hundred fifteen billion, five hundred thirty-three million, five hundred forty-four thousand, nine hundred fifty-three".