Base | Representation |
---|---|
bin | 1100001100111011000100… |
… | …0011010011110010010110 |
3 | 1202111120102210100120022001 |
4 | 3003032301003103302112 |
5 | 3224302240221100433 |
6 | 44311143514025514 |
7 | 2553166533316012 |
oct | 303166103236226 |
9 | 52446383316261 |
10 | 13416153300118 |
11 | 43028388635a8 |
12 | 160818271829a |
13 | 7641a3a659ba |
14 | 3454b9663542 |
15 | 183eb925857d |
hex | c33b10d3c96 |
13416153300118 has 4 divisors (see below), whose sum is σ = 20124229950180. Its totient is φ = 6708076650058.
The previous prime is 13416153300107. The next prime is 13416153300133. The reversal of 13416153300118 is 81100335161431.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3354038325028 + ... + 3354038325031.
It is an arithmetic number, because the mean of its divisors is an integer number (5031057487545).
Almost surely, 213416153300118 is an apocalyptic number.
13416153300118 is a deficient number, since it is larger than the sum of its proper divisors (6708076650062).
13416153300118 is an equidigital number, since it uses as much as digits as its factorization.
13416153300118 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6708076650061.
The product of its (nonzero) digits is 25920, while the sum is 37.
Adding to 13416153300118 its reverse (81100335161431), we get a palindrome (94516488461549).
The spelling of 13416153300118 in words is "thirteen trillion, four hundred sixteen billion, one hundred fifty-three million, three hundred thousand, one hundred eighteen".
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