Base | Representation |
---|---|
bin | 1100001100111011000100… |
… | …0011010011110010010101 |
3 | 1202111120102210100120022000 |
4 | 3003032301003103302111 |
5 | 3224302240221100432 |
6 | 44311143514025513 |
7 | 2553166533316011 |
oct | 303166103236225 |
9 | 52446383316260 |
10 | 13416153300117 |
11 | 43028388635a7 |
12 | 1608182718299 |
13 | 7641a3a659b9 |
14 | 3454b9663541 |
15 | 183eb925857c |
hex | c33b10d3c95 |
13416153300117 has 64 divisors (see below), whose sum is σ = 20995925448960. Its totient is φ = 8455942397952.
The previous prime is 13416153300107. The next prime is 13416153300133. The reversal of 13416153300117 is 71100335161431.
13416153300117 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 6 + 1 + 533 + 0 + 0 + 117 = 666.
It is not a de Polignac number, because 13416153300117 - 214 = 13416153283733 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13416153300107) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7481593 + ... + 9099809.
It is an arithmetic number, because the mean of its divisors is an integer number (328061335140).
Almost surely, 213416153300117 is an apocalyptic number.
It is an amenable number.
13416153300117 is a deficient number, since it is larger than the sum of its proper divisors (7579772148843).
13416153300117 is a wasteful number, since it uses less digits than its factorization.
13416153300117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1618499 (or 1618493 counting only the distinct ones).
The product of its (nonzero) digits is 22680, while the sum is 36.
Adding to 13416153300117 its reverse (71100335161431), we get a palindrome (84516488461548).
The spelling of 13416153300117 in words is "thirteen trillion, four hundred sixteen billion, one hundred fifty-three million, three hundred thousand, one hundred seventeen".
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