Search a number
-
+
1341917055737 is a prime number
BaseRepresentation
bin10011100001110000011…
…111010100101011111001
311202021201111200111210222
4103201300133110223321
5133441221231240422
62504245043345425
7165643645526066
oct23416037245371
94667644614728
101341917055737
11478116215615
121980a5382275
13997083a27bb
1448d405bdc6d
1524d8dd88842
hex138707d4af9

1341917055737 has 2 divisors, whose sum is σ = 1341917055738. Its totient is φ = 1341917055736.

The previous prime is 1341917055707. The next prime is 1341917055761. The reversal of 1341917055737 is 7375507191431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1307297243641 + 34619812096 = 1143371^2 + 186064^2 .

It is a cyclic number.

It is not a de Polignac number, because 1341917055737 - 232 = 1337622088441 is a prime.

It is a super-2 number, since 2×13419170557372 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1341917055707) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670958527868 + 670958527869.

It is an arithmetic number, because the mean of its divisors is an integer number (670958527869).

Almost surely, 21341917055737 is an apocalyptic number.

It is an amenable number.

1341917055737 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341917055737 is an equidigital number, since it uses as much as digits as its factorization.

1341917055737 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2778300, while the sum is 53.

The spelling of 1341917055737 in words is "one trillion, three hundred forty-one billion, nine hundred seventeen million, fifty-five thousand, seven hundred thirty-seven".