Base | Representation |
---|---|
bin | 10011100001110011010… |
… | …010011000001010110011 |
3 | 11202021211210000012200222 |
4 | 103201303102120022303 |
5 | 133441320240300104 |
6 | 2504253441403255 |
7 | 165645055511513 |
oct | 23416322301263 |
9 | 4667753005628 |
10 | 1341963993779 |
11 | 47813a764892 |
12 | 1980b903952b |
13 | 997150282a6 |
14 | 48d4691b843 |
15 | 24d9305b1be |
hex | 138734982b3 |
1341963993779 has 2 divisors, whose sum is σ = 1341963993780. Its totient is φ = 1341963993778.
The previous prime is 1341963993751. The next prime is 1341963993809. The reversal of 1341963993779 is 9773993691431.
It is a weak prime.
It is an emirp because it is prime and its reverse (9773993691431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1341963993779 - 224 = 1341947216563 is a prime.
It is not a weakly prime, because it can be changed into another prime (1341963993749) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670981996889 + 670981996890.
It is an arithmetic number, because the mean of its divisors is an integer number (670981996890).
Almost surely, 21341963993779 is an apocalyptic number.
1341963993779 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341963993779 is an equidigital number, since it uses as much as digits as its factorization.
1341963993779 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 208324872, while the sum is 71.
The spelling of 1341963993779 in words is "one trillion, three hundred forty-one billion, nine hundred sixty-three million, nine hundred ninety-three thousand, seven hundred seventy-nine".
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