Base | Representation |
---|---|
bin | 10011100001110011010… |
… | …010011000001010010111 |
3 | 11202021211210000012122221 |
4 | 103201303102120022113 |
5 | 133441320240300001 |
6 | 2504253441403211 |
7 | 165645055511443 |
oct | 23416322301227 |
9 | 4667753005587 |
10 | 1341963993751 |
11 | 47813a764867 |
12 | 1980b9039507 |
13 | 99715028284 |
14 | 48d4691b823 |
15 | 24d9305b1a1 |
hex | 13873498297 |
1341963993751 has 2 divisors, whose sum is σ = 1341963993752. Its totient is φ = 1341963993750.
The previous prime is 1341963993749. The next prime is 1341963993779. The reversal of 1341963993751 is 1573993691431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1341963993751 - 21 = 1341963993749 is a prime.
Together with 1341963993749, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1341963993751.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341963990751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670981996875 + 670981996876.
It is an arithmetic number, because the mean of its divisors is an integer number (670981996876).
Almost surely, 21341963993751 is an apocalyptic number.
1341963993751 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341963993751 is an equidigital number, since it uses as much as digits as its factorization.
1341963993751 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16533720, while the sum is 61.
The spelling of 1341963993751 in words is "one trillion, three hundred forty-one billion, nine hundred sixty-three million, nine hundred ninety-three thousand, seven hundred fifty-one".
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