Base | Representation |
---|---|
bin | 11000111111110100… |
… | …01000010110010010 |
3 | 1021122021112112022112 |
4 | 30133322020112102 |
5 | 204441034443010 |
6 | 10055402105322 |
7 | 653365052012 |
oct | 143772102622 |
9 | 37567475275 |
10 | 13420234130 |
11 | 5767410596 |
12 | 27264ab242 |
13 | 135b479154 |
14 | 9144b9c42 |
15 | 5382b0a05 |
hex | 31fe88592 |
13420234130 has 24 divisors (see below), whose sum is σ = 24201294156. Its totient is φ = 5358135200.
The previous prime is 13420234117. The next prime is 13420234141. The reversal of 13420234130 is 3143202431.
13420234130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 10970677081 + 2449557049 = 104741^2 + 49493^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13420234096 and 13420234105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11659055 + ... + 11660205.
Almost surely, 213420234130 is an apocalyptic number.
13420234130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13420234130 is a deficient number, since it is larger than the sum of its proper divisors (10781060026).
13420234130 is an equidigital number, since it uses as much as digits as its factorization.
13420234130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3322 (or 2171 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13420234130 its reverse (3143202431), we get a palindrome (16563436561).
The spelling of 13420234130 in words is "thirteen billion, four hundred twenty million, two hundred thirty-four thousand, one hundred thirty".
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