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134203335289 is a prime number
BaseRepresentation
bin111110011111100100…
…1000110001001111001
3110211101212020210122121
41330333021012021321
54144322023212124
6141352511121241
712460453346122
oct1747711061171
9424355223577
10134203335289
1151a08314151
1222014513221
13c86997a68a
1466d182d049
153756da12e4
hex1f3f246279

134203335289 has 2 divisors, whose sum is σ = 134203335290. Its totient is φ = 134203335288.

The previous prime is 134203335221. The next prime is 134203335307. The reversal of 134203335289 is 982533302431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79684821225 + 54518514064 = 282285^2 + 233492^2 .

It is an emirp because it is prime and its reverse (982533302431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134203335289 - 211 = 134203333241 is a prime.

It is not a weakly prime, because it can be changed into another prime (134203305289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67101667644 + 67101667645.

It is an arithmetic number, because the mean of its divisors is an integer number (67101667645).

Almost surely, 2134203335289 is an apocalyptic number.

It is an amenable number.

134203335289 is a deficient number, since it is larger than the sum of its proper divisors (1).

134203335289 is an equidigital number, since it uses as much as digits as its factorization.

134203335289 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 466560, while the sum is 43.

The spelling of 134203335289 in words is "one hundred thirty-four billion, two hundred three million, three hundred thirty-five thousand, two hundred eighty-nine".