Base | Representation |
---|---|
bin | 111110011111100100… |
… | …1000110001010001011 |
3 | 110211101212020210200021 |
4 | 1330333021012022023 |
5 | 4144322023212212 |
6 | 141352511121311 |
7 | 12460453346146 |
oct | 1747711061213 |
9 | 424355223607 |
10 | 134203335307 |
11 | 51a08314168 |
12 | 22014513237 |
13 | c86997a6a2 |
14 | 66d182d05d |
15 | 3756da1307 |
hex | 1f3f24628b |
134203335307 has 2 divisors, whose sum is σ = 134203335308. Its totient is φ = 134203335306.
The previous prime is 134203335289. The next prime is 134203335367. The reversal of 134203335307 is 703533302431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134203335307 - 215 = 134203302539 is a prime.
It is not a weakly prime, because it can be changed into another prime (134203335367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67101667653 + 67101667654.
It is an arithmetic number, because the mean of its divisors is an integer number (67101667654).
Almost surely, 2134203335307 is an apocalyptic number.
134203335307 is a deficient number, since it is larger than the sum of its proper divisors (1).
134203335307 is an equidigital number, since it uses as much as digits as its factorization.
134203335307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 34.
Adding to 134203335307 its reverse (703533302431), we get a palindrome (837736637738).
The spelling of 134203335307 in words is "one hundred thirty-four billion, two hundred three million, three hundred thirty-five thousand, three hundred seven".
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