Base | Representation |
---|---|
bin | 11110100000111011001111… |
… | …110010000100110001111111 |
3 | 122121011210001212221021201112 |
4 | 132200323033302010301333 |
5 | 120042244330220010221 |
6 | 1153232252051432235 |
7 | 40160631034252541 |
oct | 3640731762046177 |
9 | 577153055837645 |
10 | 134204034141311 |
11 | 3984167a643082 |
12 | 130757835b567b |
13 | 59b65033b6444 |
14 | 251d71d29d691 |
15 | 107ae4cc4415b |
hex | 7a0ecfc84c7f |
134204034141311 has 4 divisors (see below), whose sum is σ = 134204621472552. Its totient is φ = 134203446810072.
The previous prime is 134204034141239. The next prime is 134204034141337. The reversal of 134204034141311 is 113141430402431.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134204034141311 - 210 = 134204034140287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134204034147311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293322740 + ... + 293779913.
It is an arithmetic number, because the mean of its divisors is an integer number (33551155368138).
Almost surely, 2134204034141311 is an apocalyptic number.
134204034141311 is a deficient number, since it is larger than the sum of its proper divisors (587331241).
134204034141311 is an equidigital number, since it uses as much as digits as its factorization.
134204034141311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 587331240.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 134204034141311 its reverse (113141430402431), we get a palindrome (247345464543742).
The spelling of 134204034141311 in words is "one hundred thirty-four trillion, two hundred four billion, thirty-four million, one hundred forty-one thousand, three hundred eleven".
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