Base | Representation |
---|---|
bin | 111110011111110001… |
… | …0101011100100111101 |
3 | 110211102022212112202201 |
4 | 1330333202223210331 |
5 | 4144330232322143 |
6 | 141353310551501 |
7 | 12460564351534 |
oct | 1747742534475 |
9 | 424368775681 |
10 | 134210042173 |
11 | 51a11085129 |
12 | 22016808591 |
13 | c86b18834c |
14 | 66d269731b |
15 | 375777864d |
hex | 1f3f8ab93d |
134210042173 has 2 divisors, whose sum is σ = 134210042174. Its totient is φ = 134210042172.
The previous prime is 134210042159. The next prime is 134210042177. The reversal of 134210042173 is 371240012431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 84985076484 + 49224965689 = 291522^2 + 221867^2 .
It is a cyclic number.
It is not a de Polignac number, because 134210042173 - 221 = 134207945021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134210042177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67105021086 + 67105021087.
It is an arithmetic number, because the mean of its divisors is an integer number (67105021087).
Almost surely, 2134210042173 is an apocalyptic number.
It is an amenable number.
134210042173 is a deficient number, since it is larger than the sum of its proper divisors (1).
134210042173 is an equidigital number, since it uses as much as digits as its factorization.
134210042173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
The spelling of 134210042173 in words is "one hundred thirty-four billion, two hundred ten million, forty-two thousand, one hundred seventy-three".
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