13421040433 has 2 divisors, whose sum is σ = 13421040434. Its totient is φ = 13421040432.

The previous prime is 13421040427. The next prime is 13421040449. The reversal of 13421040433 is 33404012431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11966609664 + 1454430769 = 109392^2 + 38137^2 .

It is a cyclic number.

It is not a de Polignac number, because 13421040433 - 2⁵ = 13421040401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13421040398 and 13421040407.

It is not a weakly prime, because it can be changed into another prime (13421040533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710520216 + 6710520217.

It is an arithmetic number, because the mean of its divisors is an integer number (6710520217).

Almost surely, 2^13421040433 is an apocalyptic number.

It is an amenable number.

13421040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13421040433 is an equidigital number, since it uses as much as digits as its factorization.

13421040433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13421040433 its reverse (33404012431), we get a palindrome (46825052864).

The spelling of 13421040433 in words is "thirteen billion, four hundred twenty-one million, forty thousand, four hundred thirty-three".