Base | Representation |
---|---|
bin | 1100001101001101101001… |
… | …0010001011011000101110 |
3 | 1202112001022022202202002020 |
4 | 3003103122102023120232 |
5 | 3224342443321443042 |
6 | 44313330413011010 |
7 | 2553434234660043 |
oct | 303233222133056 |
9 | 52461268682066 |
10 | 13421140031022 |
11 | 4304967728309 |
12 | 1609134783a66 |
13 | 7647b9c29a49 |
14 | 34582da6d1ca |
15 | 1841abe3d3ec |
hex | c34da48b62e |
13421140031022 has 16 divisors (see below), whose sum is σ = 27220340345472. Its totient is φ = 4410703296440.
The previous prime is 13421140030981. The next prime is 13421140031023. The reversal of 13421140031022 is 22013004112431.
It is a super-2 number, since 2×134211400310222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13421140030983 and 13421140031001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13421140031023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15752511348 + ... + 15752512199.
It is an arithmetic number, because the mean of its divisors is an integer number (1701271271592).
Almost surely, 213421140031022 is an apocalyptic number.
13421140031022 is an abundant number, since it is smaller than the sum of its proper divisors (13799200314450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13421140031022 is a wasteful number, since it uses less digits than its factorization.
13421140031022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31505023623.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13421140031022 its reverse (22013004112431), we get a palindrome (35434144143453).
The spelling of 13421140031022 in words is "thirteen trillion, four hundred twenty-one billion, one hundred forty million, thirty-one thousand, twenty-two".
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