Base | Representation |
---|---|
bin | 1100001101001101101010… |
… | …0010111000110100110011 |
3 | 1202112001022122000021220001 |
4 | 3003103122202320310303 |
5 | 3224343000432131233 |
6 | 44313331050530431 |
7 | 2553434320132666 |
oct | 303233242706463 |
9 | 52461278007801 |
10 | 13421144411443 |
11 | 430496a14a39a |
12 | 1609136136a17 |
13 | 7647bab01802 |
14 | 34583048d6dd |
15 | 1841ac50627d |
hex | c34da8b8d33 |
13421144411443 has 2 divisors, whose sum is σ = 13421144411444. Its totient is φ = 13421144411442.
The previous prime is 13421144411429. The next prime is 13421144411593. The reversal of 13421144411443 is 34411444112431.
13421144411443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (34411444112431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13421144411443 - 217 = 13421144280371 is a prime.
It is not a weakly prime, because it can be changed into another prime (13421144411413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710572205721 + 6710572205722.
It is an arithmetic number, because the mean of its divisors is an integer number (6710572205722).
Almost surely, 213421144411443 is an apocalyptic number.
13421144411443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13421144411443 is an equidigital number, since it uses as much as digits as its factorization.
13421144411443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 73728, while the sum is 37.
Adding to 13421144411443 its reverse (34411444112431), we get a palindrome (47832588523874).
The spelling of 13421144411443 in words is "thirteen trillion, four hundred twenty-one billion, one hundred forty-four million, four hundred eleven thousand, four hundred forty-three".
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