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13421144411413 is a prime number
BaseRepresentation
bin1100001101001101101010…
…0010111000110100010101
31202112001022122000021211221
43003103122202320310111
53224343000432131123
644313331050530341
72553434320132624
oct303233242706425
952461278007757
1013421144411413
11430496a14a372
1216091361369b1
137647bab017ab
1434583048d6bb
151841ac50625d
hexc34da8b8d15

13421144411413 has 2 divisors, whose sum is σ = 13421144411414. Its totient is φ = 13421144411412.

The previous prime is 13421144411387. The next prime is 13421144411429. The reversal of 13421144411413 is 31411444112431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10356186918609 + 3064957492804 = 3218103^2 + 1750702^2 .

It is a cyclic number.

It is not a de Polignac number, because 13421144411413 - 213 = 13421144403221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13421144411443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710572205706 + 6710572205707.

It is an arithmetic number, because the mean of its divisors is an integer number (6710572205707).

Almost surely, 213421144411413 is an apocalyptic number.

It is an amenable number.

13421144411413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13421144411413 is an equidigital number, since it uses as much as digits as its factorization.

13421144411413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18432, while the sum is 34.

Adding to 13421144411413 its reverse (31411444112431), we get a palindrome (44832588523844).

The spelling of 13421144411413 in words is "thirteen trillion, four hundred twenty-one billion, one hundred forty-four million, four hundred eleven thousand, four hundred thirteen".