Base | Representation |
---|---|
bin | 1100001101001101110111… |
… | …1000100000011010001101 |
3 | 1202112001110112101022211001 |
4 | 3003103131320200122031 |
5 | 3224343104301112003 |
6 | 44313340411100301 |
7 | 2553435600123556 |
oct | 303233570403215 |
9 | 52461415338731 |
10 | 13421200410253 |
11 | 43049988180a9 |
12 | 1609150a41691 |
13 | 7647c95aa4bc |
14 | 345837aa932d |
15 | 1841b23b861d |
hex | c34dde2068d |
13421200410253 has 2 divisors, whose sum is σ = 13421200410254. Its totient is φ = 13421200410252.
The previous prime is 13421200410151. The next prime is 13421200410257. The reversal of 13421200410253 is 35201400212431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10564079559049 + 2857120851204 = 3250243^2 + 1690302^2 .
It is a cyclic number.
It is not a de Polignac number, because 13421200410253 - 233 = 13412610475661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13421200410257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710600205126 + 6710600205127.
It is an arithmetic number, because the mean of its divisors is an integer number (6710600205127).
Almost surely, 213421200410253 is an apocalyptic number.
It is an amenable number.
13421200410253 is a deficient number, since it is larger than the sum of its proper divisors (1).
13421200410253 is an equidigital number, since it uses as much as digits as its factorization.
13421200410253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 13421200410253 its reverse (35201400212431), we get a palindrome (48622600622684).
The spelling of 13421200410253 in words is "thirteen trillion, four hundred twenty-one billion, two hundred million, four hundred ten thousand, two hundred fifty-three".
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