Base | Representation |
---|---|
bin | 100111111111111… |
… | …0010100111000001 |
3 | 10110112102212212021 |
4 | 1033333302213001 |
5 | 10222040404213 |
6 | 341102201441 |
7 | 45154565251 |
oct | 11777624701 |
9 | 3415385767 |
10 | 1342122433 |
11 | 6296584a3 |
12 | 315583281 |
13 | 1850958b2 |
14 | ca367961 |
15 | 7cc60d8d |
hex | 4fff29c1 |
1342122433 has 2 divisors, whose sum is σ = 1342122434. Its totient is φ = 1342122432.
The previous prime is 1342122391. The next prime is 1342122449. The reversal of 1342122433 is 3342212431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1196606464 + 145515969 = 34592^2 + 12063^2 .
It is a cyclic number.
It is not a de Polignac number, because 1342122433 - 217 = 1341991361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1342122398 and 1342122407.
It is not a weakly prime, because it can be changed into another prime (1342132433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671061216 + 671061217.
It is an arithmetic number, because the mean of its divisors is an integer number (671061217).
Almost surely, 21342122433 is an apocalyptic number.
It is an amenable number.
1342122433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342122433 is an equidigital number, since it uses as much as digits as its factorization.
1342122433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3456, while the sum is 25.
The square root of 1342122433 is about 36634.9891906631. The cubic root of 1342122433 is about 1103.0555357265.
Adding to 1342122433 its reverse (3342212431), we get a palindrome (4684334864).
The spelling of 1342122433 in words is "one billion, three hundred forty-two million, one hundred twenty-two thousand, four hundred thirty-three".
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