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134213336249 is a prime number
BaseRepresentation
bin111110011111110111…
…1001111110010111001
3110211102120001220101112
41330333233033302321
54144332103224444
6141353505330105
712460634351336
oct1747757176271
9424376056345
10134213336249
1151a12a25003
1222017936935
13c86ba6c7c5
1466d2cb398d
153757bc969e
hex1f3fbcfcb9

134213336249 has 2 divisors, whose sum is σ = 134213336250. Its totient is φ = 134213336248.

The previous prime is 134213336137. The next prime is 134213336251. The reversal of 134213336249 is 942633312431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84270025849 + 49943310400 = 290293^2 + 223480^2 .

It is a cyclic number.

It is not a de Polignac number, because 134213336249 - 236 = 65493859513 is a prime.

Together with 134213336251, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (134213336549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67106668124 + 67106668125.

It is an arithmetic number, because the mean of its divisors is an integer number (67106668125).

Almost surely, 2134213336249 is an apocalyptic number.

It is an amenable number.

134213336249 is a deficient number, since it is larger than the sum of its proper divisors (1).

134213336249 is an equidigital number, since it uses as much as digits as its factorization.

134213336249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 279936, while the sum is 41.

The spelling of 134213336249 in words is "one hundred thirty-four billion, two hundred thirteen million, three hundred thirty-six thousand, two hundred forty-nine".