| Base | Representation |
|---|---|
| bin | 11000111111111101… |
| … | …00101100000001000 |
| 3 | 1021122100201212111102 |
| 4 | 30133332211200020 |
| 5 | 204441334331440 |
| 6 | 10055443120532 |
| 7 | 653411015150 |
| oct | 143776454010 |
| 9 | 37570655442 |
| 10 | 13421402120 |
| 11 | 5768039075 |
| 12 | 2726973148 |
| 13 | 135b797979 |
| 14 | 914701760 |
| 15 | 538441b15 |
| hex | 31ffa5808 |
13421402120 has 64 divisors (see below), whose sum is σ = 34928046720. Its totient is φ = 4546174464.
The previous prime is 13421402117. The next prime is 13421402123. The reversal of 13421402120 is 2120412431.
13421402120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13421402117) and next prime (13421402123).
It is a super-3 number, since 3×134214021203 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 13421402092 and 13421402101.
It is not an unprimeable number, because it can be changed into a prime (13421402123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 265517 + ... + 311996.
It is an arithmetic number, because the mean of its divisors is an integer number (545750730).
Almost surely, 213421402120 is an apocalyptic number.
13421402120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13421402120 is an abundant number, since it is smaller than the sum of its proper divisors (21506644600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13421402120 is a wasteful number, since it uses less digits than its factorization.
13421402120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 577614 (or 577610 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13421402120 its reverse (2120412431), we get a palindrome (15541814551).
The spelling of 13421402120 in words is "thirteen billion, four hundred twenty-one million, four hundred two thousand, one hundred twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •