Base | Representation |
---|---|
bin | 10011100001111101110… |
… | …110011111101101011101 |
3 | 11202022022010111221121002 |
4 | 103201331312133231131 |
5 | 133442201123442023 |
6 | 2504323212320045 |
7 | 165652340154056 |
oct | 23417566375535 |
9 | 4668263457532 |
10 | 1342141234013 |
11 | 478220812018 |
12 | 198148473025 |
13 | 99742973c78 |
14 | 48d6229772d |
15 | 24da38bbb28 |
hex | 1387dd9fb5d |
1342141234013 has 2 divisors, whose sum is σ = 1342141234014. Its totient is φ = 1342141234012.
The previous prime is 1342141233943. The next prime is 1342141234067. The reversal of 1342141234013 is 3104321412431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1341272045689 + 869188324 = 1158133^2 + 29482^2 .
It is a cyclic number.
It is not a de Polignac number, because 1342141234013 - 218 = 1342140971869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342141234913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671070617006 + 671070617007.
It is an arithmetic number, because the mean of its divisors is an integer number (671070617007).
Almost surely, 21342141234013 is an apocalyptic number.
It is an amenable number.
1342141234013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342141234013 is an equidigital number, since it uses as much as digits as its factorization.
1342141234013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1342141234013 its reverse (3104321412431), we get a palindrome (4446462646444).
The spelling of 1342141234013 in words is "one trillion, three hundred forty-two billion, one hundred forty-one million, two hundred thirty-four thousand, thirteen".
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