Base | Representation |
---|---|
bin | 111110011111111011… |
… | …1100011000101101111 |
3 | 110211102201011110112212 |
4 | 1330333313203011233 |
5 | 4144333132344211 |
6 | 141354024121035 |
7 | 12460662014030 |
oct | 1747767430557 |
9 | 424381143485 |
10 | 134215512431 |
11 | 51a14181000 |
12 | 2201860617b |
13 | c86c3521a0 |
14 | 66d32bca87 |
15 | 3757ea938b |
hex | 1f3fde316f |
134215512431 has 64 divisors (see below), whose sum is σ = 192385622016. Its totient is φ = 90858493440.
The previous prime is 134215512421. The next prime is 134215512433.
134215512431 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 134215512431 - 218 = 134215250287 is a prime.
It is a super-2 number, since 2×1342155124312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134215512433) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2026466 + ... + 2091648.
It is an arithmetic number, because the mean of its divisors is an integer number (3006025344).
Almost surely, 2134215512431 is an apocalyptic number.
134215512431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
134215512431 is a deficient number, since it is larger than the sum of its proper divisors (58170109585).
134215512431 is a wasteful number, since it uses less digits than its factorization.
134215512431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65253 (or 65231 counting only the distinct ones).
The product of its digits is 14400, while the sum is 32.
It can be divided in two parts, 134215 and 512431, that added together give a palindrome (646646).
The spelling of 134215512431 in words is "one hundred thirty-four billion, two hundred fifteen million, five hundred twelve thousand, four hundred thirty-one".
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