Base | Representation |
---|---|
bin | 10011100001111110101… |
… | …100101010010010100101 |
3 | 11202022100010020100010010 |
4 | 103201332230222102211 |
5 | 133442213242330000 |
6 | 2504324440520433 |
7 | 165652601642643 |
oct | 23417654522245 |
9 | 4668303210103 |
10 | 1342155433125 |
11 | 478228830021 |
12 | 198151180119 |
13 | 997458a5c00 |
14 | 48d64112193 |
15 | 24da4c73d50 |
hex | 1387eb2a4a5 |
1342155433125 has 120 divisors (see below), whose sum is σ = 2448716909760. Its totient is φ = 653315520000.
The previous prime is 1342155433123. The next prime is 1342155433133. The reversal of 1342155433125 is 5213345512431.
It is not a de Polignac number, because 1342155433125 - 21 = 1342155433123 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342155433123) by changing a digit.
It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 28178080 + ... + 28225670.
It is an arithmetic number, because the mean of its divisors is an integer number (20405974248).
Almost surely, 21342155433125 is an apocalyptic number.
1342155433125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1342155433125 is a deficient number, since it is larger than the sum of its proper divisors (1106561476635).
1342155433125 is an equidigital number, since it uses as much as digits as its factorization.
1342155433125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47729 (or 47701 counting only the distinct ones).
The product of its digits is 216000, while the sum is 39.
The spelling of 1342155433125 in words is "one trillion, three hundred forty-two billion, one hundred fifty-five million, four hundred thirty-three thousand, one hundred twenty-five".
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