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13421996761 is a prime number
BaseRepresentation
bin11001000000000001…
…10110101011011001
31021122101212002012011
430200000312223121
5204442012344021
610055503545521
7653416042615
oct144000665331
937571762164
1013421996761
115768404908
122726bbb2a1
13135b945524
14914818345
1553850cde1
hex320036ad9

13421996761 has 2 divisors, whose sum is σ = 13421996762. Its totient is φ = 13421996760.

The previous prime is 13421996759. The next prime is 13421996767. The reversal of 13421996761 is 16769912431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10204838361 + 3217158400 = 101019^2 + 56720^2 .

It is an emirp because it is prime and its reverse (16769912431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13421996761 - 21 = 13421996759 is a prime.

It is a super-2 number, since 2×134219967612 (a number of 21 digits) contains 22 as substring.

Together with 13421996759, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13421996767) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710998380 + 6710998381.

It is an arithmetic number, because the mean of its divisors is an integer number (6710998381).

Almost surely, 213421996761 is an apocalyptic number.

It is an amenable number.

13421996761 is a deficient number, since it is larger than the sum of its proper divisors (1).

13421996761 is an equidigital number, since it uses as much as digits as its factorization.

13421996761 is an evil number, because the sum of its binary digits is even.

The product of its digits is 489888, while the sum is 49.

The spelling of 13421996761 in words is "thirteen billion, four hundred twenty-one million, nine hundred ninety-six thousand, seven hundred sixty-one".