Base | Representation |
---|---|
bin | 1100001101010001010110… |
… | …0010000001011010100110 |
3 | 1202112010212121011122101002 |
4 | 3003110111202001122212 |
5 | 3224402012303241410 |
6 | 44314013202033302 |
7 | 2553500664630056 |
oct | 303242542013246 |
9 | 52463777148332 |
10 | 13422134040230 |
11 | 430532782a123 |
12 | 1609371648832 |
13 | 764917b4a186 |
14 | 3458c5a9b566 |
15 | 1842193397a5 |
hex | c35158816a6 |
13422134040230 has 8 divisors (see below), whose sum is σ = 24159841272432. Its totient is φ = 5368853616088.
The previous prime is 13422134040229. The next prime is 13422134040241. The reversal of 13422134040230 is 3204043122431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13422134040193 and 13422134040202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 671106702002 + ... + 671106702021.
It is an arithmetic number, because the mean of its divisors is an integer number (3019980159054).
Almost surely, 213422134040230 is an apocalyptic number.
13422134040230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13422134040230 is a deficient number, since it is larger than the sum of its proper divisors (10737707232202).
13422134040230 is a wasteful number, since it uses less digits than its factorization.
13422134040230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1342213404030.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 13422134040230 its reverse (3204043122431), we get a palindrome (16626177162661).
The spelling of 13422134040230 in words is "thirteen trillion, four hundred twenty-two billion, one hundred thirty-four million, forty thousand, two hundred thirty".
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