Base | Representation |
---|---|
bin | 1100001101010010110000… |
… | …1011111010010101011011 |
3 | 1202112011212002100200211121 |
4 | 3003110230023322111123 |
5 | 3224403302103320102 |
6 | 44314115020310111 |
7 | 2553513261354325 |
oct | 303245413722533 |
9 | 52464762320747 |
10 | 13422514120027 |
11 | 4305502329761 |
12 | 16094589a2337 |
13 | 76497880576c |
14 | 345920358615 |
15 | 18423c8b5b37 |
hex | c352c2fa55b |
13422514120027 has 2 divisors, whose sum is σ = 13422514120028. Its totient is φ = 13422514120026.
The previous prime is 13422514119953. The next prime is 13422514120049. The reversal of 13422514120027 is 72002141522431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13422514120027 - 27 = 13422514119899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13422514119974 and 13422514120001.
It is not a weakly prime, because it can be changed into another prime (13422514120627) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711257060013 + 6711257060014.
It is an arithmetic number, because the mean of its divisors is an integer number (6711257060014).
Almost surely, 213422514120027 is an apocalyptic number.
13422514120027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13422514120027 is an equidigital number, since it uses as much as digits as its factorization.
13422514120027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 34.
Adding to 13422514120027 its reverse (72002141522431), we get a palindrome (85424655642458).
The spelling of 13422514120027 in words is "thirteen trillion, four hundred twenty-two billion, five hundred fourteen million, one hundred twenty thousand, twenty-seven".
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