Base | Representation |
---|---|
bin | 10011100010000111111… |
… | …010100010010111011111 |
3 | 11202022201220012111000222 |
4 | 103202013322202113133 |
5 | 133443022334100011 |
6 | 2504352043111555 |
7 | 165656460205403 |
oct | 23420772422737 |
9 | 4668656174028 |
10 | 1342310065631 |
11 | 4782a8046787 |
12 | 198194b125bb |
13 | 9976b937532 |
14 | 48d7a885103 |
15 | 24db361addb |
hex | 13887ea25df |
1342310065631 has 2 divisors, whose sum is σ = 1342310065632. Its totient is φ = 1342310065630.
The previous prime is 1342310065609. The next prime is 1342310065639. The reversal of 1342310065631 is 1365600132431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1342310065631 - 210 = 1342310064607 is a prime.
It is a super-2 number, since 2×13423100656312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1342310065591 and 1342310065600.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342310065639) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671155032815 + 671155032816.
It is an arithmetic number, because the mean of its divisors is an integer number (671155032816).
Almost surely, 21342310065631 is an apocalyptic number.
1342310065631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342310065631 is an equidigital number, since it uses as much as digits as its factorization.
1342310065631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 35.
The spelling of 1342310065631 in words is "one trillion, three hundred forty-two billion, three hundred ten million, sixty-five thousand, six hundred thirty-one".
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