Base | Representation |
---|---|
bin | 1100001101010101111000… |
… | …1111110110100100111110 |
3 | 1202112021000121202201210022 |
4 | 3003111132033312210332 |
5 | 3224412012111422024 |
6 | 44314334222212142 |
7 | 2553543140345000 |
oct | 303253617664476 |
9 | 52467017681708 |
10 | 13423354014014 |
11 | 43058a343851a |
12 | 1609652124052 |
13 | 764a80815b59 |
14 | 34599db0a370 |
15 | 18428b4bd35e |
hex | c355e3f693e |
13423354014014 has 32 divisors (see below), whose sum is σ = 23485994616000. Its totient is φ = 5751663331680.
The previous prime is 13423354014001. The next prime is 13423354014029. The reversal of 13423354014014 is 41041045332431.
It is a super-2 number, since 2×134233540140142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1242284 + ... + 5328224.
It is an arithmetic number, because the mean of its divisors is an integer number (733937331750).
Almost surely, 213423354014014 is an apocalyptic number.
13423354014014 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13423354014014 is a deficient number, since it is larger than the sum of its proper divisors (10062640601986).
13423354014014 is an equidigital number, since it uses as much as digits as its factorization.
13423354014014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4090753 (or 4090739 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 13423354014014 its reverse (41041045332431), we get a palindrome (54464399346445).
The spelling of 13423354014014 in words is "thirteen trillion, four hundred twenty-three billion, three hundred fifty-four million, fourteen thousand, fourteen".
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