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1342342133047 is a prime number
BaseRepresentation
bin10011100010001001110…
…100110111010100110111
311202022211010112200021001
4103202021310313110313
5133443104041224142
62504355150304131
7165660326604406
oct23421164672467
94668733480231
101342342133047
11478314159483
121981a37b8047
1399775484536
1448d80c3163d
1524db63525b7
hex13889d37537

1342342133047 has 2 divisors, whose sum is σ = 1342342133048. Its totient is φ = 1342342133046.

The previous prime is 1342342132939. The next prime is 1342342133057. The reversal of 1342342133047 is 7403312432431.

It is a strong prime.

It is an emirp because it is prime and its reverse (7403312432431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1342342133047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1342342132997 and 1342342133015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342342133057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671171066523 + 671171066524.

It is an arithmetic number, because the mean of its divisors is an integer number (671171066524).

Almost surely, 21342342133047 is an apocalyptic number.

1342342133047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342342133047 is an equidigital number, since it uses as much as digits as its factorization.

1342342133047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 37.

Adding to 1342342133047 its reverse (7403312432431), we get a palindrome (8745654565478).

The spelling of 1342342133047 in words is "one trillion, three hundred forty-two billion, three hundred forty-two million, one hundred thirty-three thousand, forty-seven".